Base | Representation |
---|---|
bin | 100110110111010001110… |
… | …0101010010001011000011 |
3 | 200220122001120101111022102 |
4 | 1031232203211102023003 |
5 | 1200003131013341044 |
6 | 15205444455301015 |
7 | 1060621410521033 |
oct | 115564345221303 |
9 | 20818046344272 |
10 | 5341388808899 |
11 | 177a2a7807550 |
12 | 72324437a76b |
13 | 2c98c9906130 |
14 | 14674b6d38c3 |
15 | 93e1d79b24e |
hex | 4dba39522c3 |
5341388808899 has 32 divisors (see below), whose sum is σ = 6424058640384. Its totient is φ = 4376050318080.
The previous prime is 5341388808871. The next prime is 5341388808901. The reversal of 5341388808899 is 9988088831435.
5341388808899 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5341388808899 is a prime.
It is a super-3 number, since 3×53413888088993 (a number of 39 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (5341388808859) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 13374047 + ... + 13767639.
It is an arithmetic number, because the mean of its divisors is an integer number (200751832512).
Almost surely, 25341388808899 is an apocalyptic number.
5341388808899 is a deficient number, since it is larger than the sum of its proper divisors (1082669831485).
5341388808899 is a wasteful number, since it uses less digits than its factorization.
5341388808899 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 395867.
The product of its (nonzero) digits is 477757440, while the sum is 74.
The spelling of 5341388808899 in words is "five trillion, three hundred forty-one billion, three hundred eighty-eight million, eight hundred eight thousand, eight hundred ninety-nine".
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