Base | Representation |
---|---|
bin | 110001101111101111… |
… | …100110000000111011 |
3 | 12002212112112101011120 |
4 | 301233233212000323 |
5 | 1333343033330003 |
6 | 40312131000323 |
7 | 3600441345342 |
oct | 615757460073 |
9 | 162775471146 |
10 | 53414355003 |
11 | 20720013549 |
12 | a4284390a3 |
13 | 5063250729 |
14 | 2829d96b59 |
15 | 15c94d5853 |
hex | c6fbe603b |
53414355003 has 32 divisors (see below), whose sum is σ = 74573208576. Its totient is φ = 33943523328.
The previous prime is 53414354999. The next prime is 53414355031. The reversal of 53414355003 is 30055341435.
It is not a de Polignac number, because 53414355003 - 22 = 53414354999 is a prime.
It is a super-2 number, since 2×534143550032 (a number of 22 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (53414356003) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 43674250 + ... + 43675472.
It is an arithmetic number, because the mean of its divisors is an integer number (2330412768).
Almost surely, 253414355003 is an apocalyptic number.
53414355003 is a deficient number, since it is larger than the sum of its proper divisors (21158853573).
53414355003 is a wasteful number, since it uses less digits than its factorization.
53414355003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2923.
The product of its (nonzero) digits is 54000, while the sum is 33.
Adding to 53414355003 its reverse (30055341435), we get a palindrome (83469696438).
The spelling of 53414355003 in words is "fifty-three billion, four hundred fourteen million, three hundred fifty-five thousand, three".
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