Base | Representation |
---|---|
bin | 100110110111010101101… |
… | …1010111110101011010111 |
3 | 200220122101201212012221112 |
4 | 1031232223122332223113 |
5 | 1200003413200402320 |
6 | 15205505514205235 |
7 | 1060624565425625 |
oct | 115565332765327 |
9 | 20818351765845 |
10 | 5341520325335 |
11 | 177a364a74817 |
12 | 72328042381b |
13 | 2c991ac32bcc |
14 | 146760d6a515 |
15 | 93e2a0c8ec5 |
hex | 4dbab6bead7 |
5341520325335 has 16 divisors (see below), whose sum is σ = 6737333685696. Its totient is φ = 4057589023488.
The previous prime is 5341520325311. The next prime is 5341520325367. The reversal of 5341520325335 is 5335230251435.
It is a cyclic number.
It is not a de Polignac number, because 5341520325335 - 28 = 5341520325079 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5341520325292 and 5341520325301.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 169502504 + ... + 169534013.
It is an arithmetic number, because the mean of its divisors is an integer number (421083355356).
Almost surely, 25341520325335 is an apocalyptic number.
5341520325335 is a deficient number, since it is larger than the sum of its proper divisors (1395813360361).
5341520325335 is a wasteful number, since it uses less digits than its factorization.
5341520325335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 339036682.
The product of its (nonzero) digits is 810000, while the sum is 41.
The spelling of 5341520325335 in words is "five trillion, three hundred forty-one billion, five hundred twenty million, three hundred twenty-five thousand, three hundred thirty-five".
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