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53420263530013 = 56394885015151
BaseRepresentation
bin11000010010101110111111…
…10101001101111000011101
321000010221001000101220001101
430021113133311031320131
524000214144430430023
6305340532534513101
714152325633636212
oct1411273765157035
9230127030356041
1053420263530013
1116026452110186
125ba9256205791
1323a6680a37a53
14d297a9987b09
156298b4c211ad
hex3095dfd4de1d

53420263530013 has 4 divisors (see below), whose sum is σ = 53515148545728. Its totient is φ = 53325378514300.

The previous prime is 53420263529993. The next prime is 53420263530037. The reversal of 53420263530013 is 31003536202435.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 53420263530013 - 25 = 53420263529981 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53420263531013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47442507013 + ... + 47442508138.

It is an arithmetic number, because the mean of its divisors is an integer number (13378787136432).

Almost surely, 253420263530013 is an apocalyptic number.

It is an amenable number.

53420263530013 is a deficient number, since it is larger than the sum of its proper divisors (94885015715).

53420263530013 is an equidigital number, since it uses as much as digits as its factorization.

53420263530013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 94885015714.

The product of its (nonzero) digits is 194400, while the sum is 37.

Adding to 53420263530013 its reverse (31003536202435), we get a palindrome (84423799732448).

The spelling of 53420263530013 in words is "fifty-three trillion, four hundred twenty billion, two hundred sixty-three million, five hundred thirty thousand, thirteen".

Divisors: 1 563 94885015151 53420263530013