Base | Representation |
---|---|
bin | 110001110000000111… |
… | …001101000110010011 |
3 | 12002212222011211102121 |
4 | 301300013031012103 |
5 | 1333401124410103 |
6 | 40312511355111 |
7 | 3600545064262 |
oct | 616007150623 |
9 | 162788154377 |
10 | 53420544403 |
11 | 20723560756 |
12 | a42a522a97 |
13 | 50646099b5 |
14 | 282ab285d9 |
15 | 15c9d096bd |
hex | c701cd193 |
53420544403 has 4 divisors (see below), whose sum is σ = 53426684248. Its totient is φ = 53414404560.
The previous prime is 53420544391. The next prime is 53420544409. The reversal of 53420544403 is 30444502435.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30444502435 = 5 ⋅6088900487.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53420544403 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (53420544409) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3056853 + ... + 3074278.
It is an arithmetic number, because the mean of its divisors is an integer number (13356671062).
Almost surely, 253420544403 is an apocalyptic number.
53420544403 is a deficient number, since it is larger than the sum of its proper divisors (6139845).
53420544403 is an equidigital number, since it uses as much as digits as its factorization.
53420544403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6139844.
The product of its (nonzero) digits is 115200, while the sum is 34.
The spelling of 53420544403 in words is "fifty-three billion, four hundred twenty million, five hundred forty-four thousand, four hundred three".
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