Base | Representation |
---|---|
bin | 11000010010110001001000… |
… | …01011011101011000000111 |
3 | 21000011000222221002100002222 |
4 | 30021120210023131120013 |
5 | 24000224022003230320 |
6 | 305341242420122555 |
7 | 14152366226365355 |
oct | 1411304413353007 |
9 | 230130887070088 |
10 | 53421410211335 |
11 | 160269904098a1 |
12 | 5ba951623645b |
13 | 23a68044813ca |
14 | d29877d987d5 |
15 | 629930728825 |
hex | 3096242dd607 |
53421410211335 has 16 divisors (see below), whose sum is σ = 64537652508672. Its totient is φ = 42449219748000.
The previous prime is 53421410211331. The next prime is 53421410211353. The reversal of 53421410211335 is 53311201412435.
It is not a de Polignac number, because 53421410211335 - 22 = 53421410211331 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 53421410211295 and 53421410211304.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53421410211331) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2510570 + ... + 10637000.
It is an arithmetic number, because the mean of its divisors is an integer number (4033603281792).
Almost surely, 253421410211335 is an apocalyptic number.
53421410211335 is a deficient number, since it is larger than the sum of its proper divisors (11116242297337).
53421410211335 is a wasteful number, since it uses less digits than its factorization.
53421410211335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8135294.
The product of its (nonzero) digits is 43200, while the sum is 35.
The spelling of 53421410211335 in words is "fifty-three trillion, four hundred twenty-one billion, four hundred ten million, two hundred eleven thousand, three hundred thirty-five".
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