Base | Representation |
---|---|
bin | 111100101111101000000110… |
… | …0100100111100101101101001 |
3 | 2121001211122220202011221012102 |
4 | 1321133100030210330231221 |
5 | 1030013124042030112131 |
6 | 5132215122152423145 |
7 | 220354501445233505 |
oct | 17137201444745551 |
9 | 2531748822157172 |
10 | 534311322504041 |
11 | 1452801830a4645 |
12 | 4bb151449a7ab5 |
13 | 19c1a4594017a4 |
14 | 95d2b3d909305 |
15 | 41b89e4d871cb |
hex | 1e5f40c93cb69 |
534311322504041 has 4 divisors (see below), whose sum is σ = 534756211200084. Its totient is φ = 533866433808000.
The previous prime is 534311322503989. The next prime is 534311322504053. The reversal of 534311322504041 is 140405223113435.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 232118296814041 + 302193025690000 = 15235429^2 + 17383700^2 .
It is a cyclic number.
It is not a de Polignac number, because 534311322504041 - 26 = 534311322503977 is a prime.
It is a super-2 number, since 2×5343113225040412 (a number of 30 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 534311322503986 and 534311322504004.
It is not an unprimeable number, because it can be changed into a prime (534311322504941) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 222444346220 + ... + 222444348621.
It is an arithmetic number, because the mean of its divisors is an integer number (133689052800021).
Almost surely, 2534311322504041 is an apocalyptic number.
It is an amenable number.
534311322504041 is a deficient number, since it is larger than the sum of its proper divisors (444888696043).
534311322504041 is a wasteful number, since it uses less digits than its factorization.
534311322504041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 444888696042.
The product of its (nonzero) digits is 172800, while the sum is 38.
Adding to 534311322504041 its reverse (140405223113435), we get a palindrome (674716545617476).
The spelling of 534311322504041 in words is "five hundred thirty-four trillion, three hundred eleven billion, three hundred twenty-two million, five hundred four thousand, forty-one".
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