Base | Representation |
---|---|
bin | 111100101111101001010110… |
… | …1011011000011010000111011 |
3 | 2121001211220212210221211021112 |
4 | 1321133102231123003100323 |
5 | 1030013200103341304321 |
6 | 5132220250031430535 |
7 | 220354625353355015 |
oct | 17137225533032073 |
9 | 2531756783854245 |
10 | 534314021041211 |
11 | 145281338381554 |
12 | 4bb1577868544b |
13 | 19c1a7994c5448 |
14 | 95d2d1807b1b5 |
15 | 41b8b01c2da5b |
hex | 1e5f4ad6c343b |
534314021041211 has 4 divisors (see below), whose sum is σ = 535746498309792. Its totient is φ = 532881543772632.
The previous prime is 534314021041193. The next prime is 534314021041217. The reversal of 534314021041211 is 112140120413435.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-534314021041211 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (534314021041217) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 716238633731 + ... + 716238634476.
It is an arithmetic number, because the mean of its divisors is an integer number (133936624577448).
Almost surely, 2534314021041211 is an apocalyptic number.
534314021041211 is a deficient number, since it is larger than the sum of its proper divisors (1432477268581).
534314021041211 is a wasteful number, since it uses less digits than its factorization.
534314021041211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1432477268580.
The product of its (nonzero) digits is 11520, while the sum is 32.
Adding to 534314021041211 its reverse (112140120413435), we get a palindrome (646454141454646).
The spelling of 534314021041211 in words is "five hundred thirty-four trillion, three hundred fourteen billion, twenty-one million, forty-one thousand, two hundred eleven".
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