534315041133 has 4 divisors (see below), whose sum is σ = 712420054848. Its totient is φ = 356210027420.

The previous prime is 534315041087. The next prime is 534315041137. The reversal of 534315041133 is 331140513435.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 534315041133 - 2²⁵ = 534281486701 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 534315041094 and 534315041103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (534315041137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 89052506853 + ... + 89052506858.

It is an arithmetic number, because the mean of its divisors is an integer number (178105013712).

Almost surely, 2^534315041133 is an apocalyptic number.

It is an amenable number.

534315041133 is a deficient number, since it is larger than the sum of its proper divisors (178105013715).

534315041133 is a wasteful number, since it uses less digits than its factorization.

534315041133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 178105013714.

The product of its (nonzero) digits is 32400, while the sum is 33.

Adding to 534315041133 its reverse (331140513435), we get a palindrome (865455554568).

The spelling of 534315041133 in words is "five hundred thirty-four billion, three hundred fifteen million, forty-one thousand, one hundred thirty-three".