Base | Representation |
---|---|
bin | 110001110000110001… |
… | …011001000110011101 |
3 | 12002220201222200210222 |
4 | 301300301121012131 |
5 | 1333411442303423 |
6 | 40313544411125 |
7 | 3601041065003 |
oct | 616061310635 |
9 | 162821880728 |
10 | 53431603613 |
11 | 207298246a3 |
12 | a432176aa5 |
13 | 50669ac6cb |
14 | 282c3a6a73 |
15 | 15cac913c8 |
hex | c70c5919d |
53431603613 has 4 divisors (see below), whose sum is σ = 53559125760. Its totient is φ = 53304081468.
The previous prime is 53431603609. The next prime is 53431603637. The reversal of 53431603613 is 31630613435.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 53431603613 - 22 = 53431603609 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53431603513) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 63760445 + ... + 63761282.
It is an arithmetic number, because the mean of its divisors is an integer number (13389781440).
Almost surely, 253431603613 is an apocalyptic number.
It is an amenable number.
53431603613 is a deficient number, since it is larger than the sum of its proper divisors (127522147).
53431603613 is a wasteful number, since it uses less digits than its factorization.
53431603613 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 127522146.
The product of its (nonzero) digits is 58320, while the sum is 35.
The spelling of 53431603613 in words is "fifty-three billion, four hundred thirty-one million, six hundred three thousand, six hundred thirteen".
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