Base | Representation |
---|---|
bin | 111100101111101110101001… |
… | …1101010110001110011111101 |
3 | 2121001220000020211200202000121 |
4 | 1321133131103222301303331 |
5 | 1030013341404412211402 |
6 | 5132225411120454541 |
7 | 220355510345042404 |
oct | 17137352352616375 |
9 | 2531800224622017 |
10 | 534325400116477 |
11 | 145286147593192 |
12 | 4bb17a1347a451 |
13 | 19c1b890b16088 |
14 | 95d36b742663b |
15 | 41b906abeb837 |
hex | 1e5f753ab1cfd |
534325400116477 has 4 divisors (see below), whose sum is σ = 557556939252000. Its totient is φ = 511093860980956.
The previous prime is 534325400116439. The next prime is 534325400116483. The reversal of 534325400116477 is 774611004523435.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-534325400116477 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (534325401116477) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11615769567727 + ... + 11615769567772.
It is an arithmetic number, because the mean of its divisors is an integer number (139389234813000).
Almost surely, 2534325400116477 is an apocalyptic number.
It is an amenable number.
534325400116477 is a deficient number, since it is larger than the sum of its proper divisors (23231539135523).
534325400116477 is a wasteful number, since it uses less digits than its factorization.
534325400116477 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23231539135522.
The product of its (nonzero) digits is 8467200, while the sum is 52.
The spelling of 534325400116477 in words is "five hundred thirty-four trillion, three hundred twenty-five billion, four hundred million, one hundred sixteen thousand, four hundred seventy-seven".
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