Search a number
-
+
53433123331 = 719922743541
BaseRepresentation
bin110001110000110111…
…001100001000000011
312002220211211220110211
4301300313030020003
51333412334421311
640314041134551
73601060024450
oct616067141003
9162824756424
1053433123331
112072a672465
12a43278a457
1350670c2353
14282c680827
1515cae91821
hexc70dcc203

53433123331 has 16 divisors (see below), whose sum is σ = 64288892160. Its totient is φ = 43383604320.

The previous prime is 53433123313. The next prime is 53433123343. The reversal of 53433123331 is 13332133435.

It is not a de Polignac number, because 53433123331 - 25 = 53433123299 is a prime.

It is a super-2 number, since 2×534331233312 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 53433123293 and 53433123302.

It is not an unprimeable number, because it can be changed into a prime (53433123311) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1205421 + ... + 1248961.

It is an arithmetic number, because the mean of its divisors is an integer number (4018055760).

Almost surely, 253433123331 is an apocalyptic number.

53433123331 is a deficient number, since it is larger than the sum of its proper divisors (10855768829).

53433123331 is a wasteful number, since it uses less digits than its factorization.

53433123331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 52794.

The product of its digits is 29160, while the sum is 31.

Adding to 53433123331 its reverse (13332133435), we get a palindrome (66765256766).

The spelling of 53433123331 in words is "fifty-three billion, four hundred thirty-three million, one hundred twenty-three thousand, three hundred thirty-one".

Divisors: 1 7 19 133 9227 43541 64589 175313 304787 827279 1227191 5790953 401752807 2812269649 7633303333 53433123331