53433123313 has 2 divisors, whose sum is σ = 53433123314. Its totient is φ = 53433123312.

The previous prime is 53433123311. The next prime is 53433123343. The reversal of 53433123313 is 31332133435.

53433123313 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 34273857424 + 19159265889 = 185132^2 + 138417^2 .

It is a cyclic number.

It is not a de Polignac number, because 53433123313 - 2¹ = 53433123311 is a prime.

Together with 53433123311, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (53433123311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26716561656 + 26716561657.

It is an arithmetic number, because the mean of its divisors is an integer number (26716561657).

Almost surely, 2^53433123313 is an apocalyptic number.

It is an amenable number.

53433123313 is a deficient number, since it is larger than the sum of its proper divisors (1).

53433123313 is an equidigital number, since it uses as much as digits as its factorization.

53433123313 is an evil number, because the sum of its binary digits is even.

The product of its digits is 29160, while the sum is 31.

Adding to 53433123313 its reverse (31332133435), we get a palindrome (84765256748).

The spelling of 53433123313 in words is "fifty-three billion, four hundred thirty-three million, one hundred twenty-three thousand, three hundred thirteen".