Base | Representation |
---|---|
bin | 110001110000111011… |
… | …000101010100001011 |
3 | 12002220220202202120210 |
4 | 301300323011110023 |
5 | 1333413120102021 |
6 | 40314115052203 |
7 | 3601101505263 |
oct | 616073052413 |
9 | 162826682523 |
10 | 53434144011 |
11 | 207301aa2a6 |
12 | a432ba1063 |
13 | 506738bac1 |
14 | 282c8687a3 |
15 | 15cb0e3e76 |
hex | c70ec550b |
53434144011 has 8 divisors (see below), whose sum is σ = 74995289920. Its totient is φ = 33747880392.
The previous prime is 53434143989. The next prime is 53434144013. The reversal of 53434144011 is 11044143435.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 53434144011 - 26 = 53434143947 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 53434144011.
It is not an unprimeable number, because it can be changed into a prime (53434144013) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 468720505 + ... + 468720618.
It is an arithmetic number, because the mean of its divisors is an integer number (9374411240).
Almost surely, 253434144011 is an apocalyptic number.
53434144011 is a deficient number, since it is larger than the sum of its proper divisors (21561145909).
53434144011 is a wasteful number, since it uses less digits than its factorization.
53434144011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 937441145.
The product of its (nonzero) digits is 11520, while the sum is 30.
Adding to 53434144011 its reverse (11044143435), we get a palindrome (64478287446).
The spelling of 53434144011 in words is "fifty-three billion, four hundred thirty-four million, one hundred forty-four thousand, eleven".
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