Base | Representation |
---|---|
bin | 110001110000111101… |
… | …111111000101100111 |
3 | 12002220222012102101011 |
4 | 301300331333011213 |
5 | 1333413313424220 |
6 | 40314143243051 |
7 | 3601111124566 |
oct | 616075770547 |
9 | 162828172334 |
10 | 53434904935 |
11 | 20730679a65 |
12 | a4332a9487 |
13 | 5067597259 |
14 | 282c9c5bdd |
15 | 15cb1e465a |
hex | c70f7f167 |
53434904935 has 4 divisors (see below), whose sum is σ = 64121885928. Its totient is φ = 42747923944.
The previous prime is 53434904911. The next prime is 53434904969. The reversal of 53434904935 is 53940943435.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 53434904935 - 29 = 53434904423 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5343490489 + ... + 5343490498.
It is an arithmetic number, because the mean of its divisors is an integer number (16030471482).
Almost surely, 253434904935 is an apocalyptic number.
53434904935 is a deficient number, since it is larger than the sum of its proper divisors (10686980993).
53434904935 is a wasteful number, since it uses less digits than its factorization.
53434904935 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10686980992.
The product of its (nonzero) digits is 3499200, while the sum is 49.
The spelling of 53434904935 in words is "fifty-three billion, four hundred thirty-four million, nine hundred four thousand, nine hundred thirty-five".
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