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534354112360391 = 1049527509138033
BaseRepresentation
bin111100101111111100000001…
…1000011010010111111000111
32121001222202100211211212010212
41321133320003003102333013
51030014324210231013031
65132250520151510035
7220360545020064341
oct17137700303227707
92531882324755125
10534354112360391
11145297340931a94
124bb214a708831b
1319c214b846c20b
1495d4c3c81a291
1541b9b9b75312b
hex1e5fe030d2fc7

534354112360391 has 4 divisors (see below), whose sum is σ = 534354622547952. Its totient is φ = 534353602172832.

The previous prime is 534354112360351. The next prime is 534354112360417. The reversal of 534354112360391 is 193063211453435.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 534354112360391 - 214 = 534354112344007 is a prime.

It is a super-2 number, since 2×5343541123603912 (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (534354112360351) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 253519490 + ... + 255618543.

It is an arithmetic number, because the mean of its divisors is an integer number (133588655636988).

Almost surely, 2534354112360391 is an apocalyptic number.

534354112360391 is a deficient number, since it is larger than the sum of its proper divisors (510187561).

534354112360391 is a wasteful number, since it uses less digits than its factorization.

534354112360391 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 510187560.

The product of its (nonzero) digits is 3499200, while the sum is 50.

The spelling of 534354112360391 in words is "five hundred thirty-four trillion, three hundred fifty-four billion, one hundred twelve million, three hundred sixty thousand, three hundred ninety-one".

Divisors: 1 1049527 509138033 534354112360391