Base | Representation |
---|---|
bin | 110001110001001010… |
… | …111000101011100011 |
3 | 12002221012120020002122 |
4 | 301301022320223203 |
5 | 1333420200132223 |
6 | 40314343534455 |
7 | 3601151640554 |
oct | 616112705343 |
9 | 162835506078 |
10 | 53438286563 |
11 | 207325796a2 |
12 | a43445a42b |
13 | 50681ac50c |
14 | 282d22632b |
15 | 15cb6615c8 |
hex | c712b8ae3 |
53438286563 has 4 divisors (see below), whose sum is σ = 54741659448. Its totient is φ = 52134913680.
The previous prime is 53438286547. The next prime is 53438286571. The reversal of 53438286563 is 36568283435.
53438286563 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 53438286563 - 24 = 53438286547 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (53438280563) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 651686381 + ... + 651686462.
It is an arithmetic number, because the mean of its divisors is an integer number (13685414862).
Almost surely, 253438286563 is an apocalyptic number.
53438286563 is a deficient number, since it is larger than the sum of its proper divisors (1303372885).
53438286563 is a wasteful number, since it uses less digits than its factorization.
53438286563 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1303372884.
The product of its digits is 12441600, while the sum is 53.
The spelling of 53438286563 in words is "fifty-three billion, four hundred thirty-eight million, two hundred eighty-six thousand, five hundred sixty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.081 sec. • engine limits •