Base | Representation |
---|---|
bin | 111100110000010011111011… |
… | …0011100011000101110100011 |
3 | 2121002011122211222200112012201 |
4 | 1321200213312130120232203 |
5 | 1030021144320223110001 |
6 | 5132330245314434031 |
7 | 220364342666424061 |
oct | 17140476634305643 |
9 | 2532148758615181 |
10 | 534405440441251 |
11 | 145307090231925 |
12 | 4bb2b430892917 |
13 | 19c262a83c94b2 |
14 | 95d750b69b031 |
15 | 41bb1a29d3501 |
hex | 1e609f6718ba3 |
534405440441251 has 32 divisors (see below), whose sum is σ = 592071453642240. Its totient is φ = 480083460519936.
The previous prime is 534405440441167. The next prime is 534405440441261. The reversal of 534405440441251 is 152144044504435.
It is a cyclic number.
It is not a de Polignac number, because 534405440441251 - 217 = 534405440310179 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (534405440441261) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2275795 + ... + 32771788.
It is an arithmetic number, because the mean of its divisors is an integer number (18502232926320).
Almost surely, 2534405440441251 is an apocalyptic number.
534405440441251 is a deficient number, since it is larger than the sum of its proper divisors (57666013200989).
534405440441251 is a wasteful number, since it uses less digits than its factorization.
534405440441251 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 35047983.
The product of its (nonzero) digits is 3072000, while the sum is 46.
Adding to 534405440441251 its reverse (152144044504435), we get a palindrome (686549484945686).
The spelling of 534405440441251 in words is "five hundred thirty-four trillion, four hundred five billion, four hundred forty million, four hundred forty-one thousand, two hundred fifty-one".
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