Base | Representation |
---|---|
bin | 1111100011011011111… |
… | …00001100101110111001 |
3 | 1220002102200100100010020 |
4 | 13301231330030232321 |
5 | 32223443113121131 |
6 | 1045302004441053 |
7 | 53416302543333 |
oct | 7615574145671 |
9 | 1802380310106 |
10 | 534420442041 |
11 | 196712453012 |
12 | 876a83a9189 |
13 | 3b51b282545 |
14 | 1bc1a788453 |
15 | dd7c882996 |
hex | 7c6df0cbb9 |
534420442041 has 16 divisors (see below), whose sum is σ = 727951699200. Its totient is φ = 348589536768.
The previous prime is 534420442037. The next prime is 534420442057. The reversal of 534420442041 is 140244024435.
It is not a de Polignac number, because 534420442041 - 22 = 534420442037 is a prime.
It is a super-3 number, since 3×5344204420413 (a number of 36 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 534420441993 and 534420442011.
It is not an unprimeable number, because it can be changed into a prime (534420442001) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 151186 + ... + 1044843.
It is an arithmetic number, because the mean of its divisors is an integer number (45496981200).
Almost surely, 2534420442041 is an apocalyptic number.
It is an amenable number.
534420442041 is a deficient number, since it is larger than the sum of its proper divisors (193531257159).
534420442041 is a wasteful number, since it uses less digits than its factorization.
534420442041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1199248.
The product of its (nonzero) digits is 61440, while the sum is 33.
Adding to 534420442041 its reverse (140244024435), we get a palindrome (674664466476).
The spelling of 534420442041 in words is "five hundred thirty-four billion, four hundred twenty million, four hundred forty-two thousand, forty-one".
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