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534420442041 = 34731691196029
BaseRepresentation
bin1111100011011011111…
…00001100101110111001
31220002102200100100010020
413301231330030232321
532223443113121131
61045302004441053
753416302543333
oct7615574145671
91802380310106
10534420442041
11196712453012
12876a83a9189
133b51b282545
141bc1a788453
15dd7c882996
hex7c6df0cbb9

534420442041 has 16 divisors (see below), whose sum is σ = 727951699200. Its totient is φ = 348589536768.

The previous prime is 534420442037. The next prime is 534420442057. The reversal of 534420442041 is 140244024435.

It is not a de Polignac number, because 534420442041 - 22 = 534420442037 is a prime.

It is a super-3 number, since 3×5344204420413 (a number of 36 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 534420441993 and 534420442011.

It is not an unprimeable number, because it can be changed into a prime (534420442001) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 151186 + ... + 1044843.

It is an arithmetic number, because the mean of its divisors is an integer number (45496981200).

Almost surely, 2534420442041 is an apocalyptic number.

It is an amenable number.

534420442041 is a deficient number, since it is larger than the sum of its proper divisors (193531257159).

534420442041 is a wasteful number, since it uses less digits than its factorization.

534420442041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1199248.

The product of its (nonzero) digits is 61440, while the sum is 33.

Adding to 534420442041 its reverse (140244024435), we get a palindrome (674664466476).

The spelling of 534420442041 in words is "five hundred thirty-four billion, four hundred twenty million, four hundred forty-two thousand, forty-one".

Divisors: 1 3 47 141 3169 9507 148943 446829 1196029 3588087 56213363 168640089 3790215901 11370647703 178140147347 534420442041