534433504042 has 4 divisors (see below), whose sum is σ = 801650256066. Its totient is φ = 267216752020.

The previous prime is 534433504019. The next prime is 534433504057. The reversal of 534433504042 is 240405334435.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 524105050401 + 10328453641 = 723951^2 + 101629^2 .

It is a super-3 number, since 3×534433504042³ (a number of 36 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 534433503992 and 534433504010.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 133608376009 + ... + 133608376012.

Almost surely, 2^534433504042 is an apocalyptic number.

534433504042 is a deficient number, since it is larger than the sum of its proper divisors (267216752024).

534433504042 is a wasteful number, since it uses less digits than its factorization.

534433504042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 267216752023.

The product of its (nonzero) digits is 345600, while the sum is 37.

Adding to 534433504042 its reverse (240405334435), we get a palindrome (774838838477).

The spelling of 534433504042 in words is "five hundred thirty-four billion, four hundred thirty-three million, five hundred four thousand, forty-two".