Base | Representation |
---|---|
bin | 11000010011100110100100… |
… | …11101101100111110001001 |
3 | 21000020210001122120111212200 |
4 | 30021303102131230332021 |
5 | 24001211303113030121 |
6 | 305402345552230413 |
7 | 14154433256012523 |
oct | 1411632235547611 |
9 | 230223048514780 |
10 | 53450104033161 |
11 | 16038075315930 |
12 | 5bb2ba383b409 |
13 | 23a94280573c4 |
14 | d2addab54a13 |
15 | 62a55e841a26 |
hex | 309cd276cf89 |
53450104033161 has 24 divisors (see below), whose sum is σ = 84230709361344. Its totient is φ = 32391578211360.
The previous prime is 53450104033159. The next prime is 53450104033177. The reversal of 53450104033161 is 16133040105435.
53450104033161 is a `hidden beast` number, since 5 + 3 + 450 + 1 + 0 + 40 + 3 + 3 + 161 = 666.
It is not a de Polignac number, because 53450104033161 - 21 = 53450104033159 is a prime.
It is not an unprimeable number, because it can be changed into a prime (53450104033141) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 18871926 + ... + 21518591.
It is an arithmetic number, because the mean of its divisors is an integer number (3509612890056).
Almost surely, 253450104033161 is an apocalyptic number.
It is an amenable number.
53450104033161 is a deficient number, since it is larger than the sum of its proper divisors (30780605328183).
53450104033161 is a wasteful number, since it uses less digits than its factorization.
53450104033161 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 40403901 (or 40403898 counting only the distinct ones).
The product of its (nonzero) digits is 64800, while the sum is 36.
Adding to 53450104033161 its reverse (16133040105435), we get a palindrome (69583144138596).
The spelling of 53450104033161 in words is "fifty-three trillion, four hundred fifty billion, one hundred four million, thirty-three thousand, one hundred sixty-one".
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