Base | Representation |
---|---|
bin | 100110111000111101110… |
… | …0100110011101001110111 |
3 | 200220222102010010020210122 |
4 | 1031301323210303221313 |
5 | 1200033041204000201 |
6 | 15211244225042155 |
7 | 1061110252104344 |
oct | 115617344635167 |
9 | 20828363106718 |
10 | 5345012562551 |
11 | 178089727a282 |
12 | 723a95a8635b |
13 | 2ca0565b206c |
14 | 1469b2aa77cb |
15 | 940819a0e1b |
hex | 4dc7b933a77 |
5345012562551 has 4 divisors (see below), whose sum is σ = 5529323340600. Its totient is φ = 5160701784504.
The previous prime is 5345012562481. The next prime is 5345012562563. The reversal of 5345012562551 is 1552652105435.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5345012562551 - 234 = 5327832693367 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5345012562451) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 92155388981 + ... + 92155389038.
It is an arithmetic number, because the mean of its divisors is an integer number (1382330835150).
Almost surely, 25345012562551 is an apocalyptic number.
5345012562551 is a deficient number, since it is larger than the sum of its proper divisors (184310778049).
5345012562551 is a wasteful number, since it uses less digits than its factorization.
5345012562551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 184310778048.
The product of its (nonzero) digits is 900000, while the sum is 44.
Adding to 5345012562551 its reverse (1552652105435), we get a palindrome (6897664667986).
The spelling of 5345012562551 in words is "five trillion, three hundred forty-five billion, twelve million, five hundred sixty-two thousand, five hundred fifty-one".
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