Base | Representation |
---|---|
bin | 11000010011101000101000… |
… | …11110010110101011001011 |
3 | 21000020212220211110200002201 |
4 | 30021310110132112223023 |
5 | 24001221040121001420 |
6 | 305403051513141031 |
7 | 14154502564225513 |
oct | 1411642436265313 |
9 | 230225824420081 |
10 | 53451211500235 |
11 | 1603859347027a |
12 | 5bb32526ba777 |
13 | 23a9573620a73 |
14 | d2b0a3c78843 |
15 | 62a5c6ba010a |
hex | 309d14796acb |
53451211500235 has 16 divisors (see below), whose sum is σ = 65188084824000. Its totient is φ = 42068043933696.
The previous prime is 53451211500221. The next prime is 53451211500367. The reversal of 53451211500235 is 53200511215435.
53451211500235 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 53451211500235 - 211 = 53451211498187 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 53451211500194 and 53451211500203.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 301708134 + ... + 301885243.
It is an arithmetic number, because the mean of its divisors is an integer number (4074255301500).
Almost surely, 253451211500235 is an apocalyptic number.
53451211500235 is a deficient number, since it is larger than the sum of its proper divisors (11736873323765).
53451211500235 is a wasteful number, since it uses less digits than its factorization.
53451211500235 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 603593670.
The product of its (nonzero) digits is 90000, while the sum is 37.
The spelling of 53451211500235 in words is "fifty-three trillion, four hundred fifty-one billion, two hundred eleven million, five hundred thousand, two hundred thirty-five".
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