Base | Representation |
---|---|
bin | 11000010100101111000101… |
… | …01001011110011111100111 |
3 | 21000101111112111010202111011 |
4 | 30022113202221132133213 |
5 | 24002331013221320321 |
6 | 305432304332323051 |
7 | 14160312014334433 |
oct | 1412274251363747 |
9 | 230344474122434 |
10 | 53489030260711 |
11 | 16052630142821 |
12 | 5bba648013487 |
13 | 23accbc80cb46 |
14 | d2cc5088d9c3 |
15 | 62b58be23ae1 |
hex | 30a5e2a5e7e7 |
53489030260711 has 4 divisors (see below), whose sum is σ = 53503917275232. Its totient is φ = 53474143246192.
The previous prime is 53489030260651. The next prime is 53489030260777. The reversal of 53489030260711 is 11706203098435.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 53489030260711 - 223 = 53489021872103 is a prime.
It is a super-2 number, since 2×534890302607112 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53489030290711) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7443501871 + ... + 7443509056.
It is an arithmetic number, because the mean of its divisors is an integer number (13375979318808).
It is a 1-persistent number, because it is pandigital, but 2⋅53489030260711 = 106978060521422 is not.
Almost surely, 253489030260711 is an apocalyptic number.
53489030260711 is a deficient number, since it is larger than the sum of its proper divisors (14887014521).
53489030260711 is a wasteful number, since it uses less digits than its factorization.
53489030260711 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14887014520.
The product of its (nonzero) digits is 1088640, while the sum is 49.
The spelling of 53489030260711 in words is "fifty-three trillion, four hundred eighty-nine billion, thirty million, two hundred sixty thousand, seven hundred eleven".
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