Base | Representation |
---|---|
bin | 110001110100010001… |
… | …010001000111111011 |
3 | 12010001211102100001010 |
4 | 301310101101013323 |
5 | 1334022003304240 |
6 | 40323442325003 |
7 | 3602352654555 |
oct | 616421210773 |
9 | 163054370033 |
10 | 53490291195 |
11 | 20759969530 |
12 | a449959763 |
13 | 5075bba1a3 |
14 | 28360c24d5 |
15 | 15d0ed5280 |
hex | c744511fb |
53490291195 has 64 divisors (see below), whose sum is σ = 96249254400. Its totient is φ = 25145533440.
The previous prime is 53490291161. The next prime is 53490291203. The reversal of 53490291195 is 59119209435.
53490291195 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 53490291195 - 211 = 53490289147 is a prime.
It is a super-2 number, since 2×534902911952 (a number of 22 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 673021 + ... + 748289.
It is an arithmetic number, because the mean of its divisors is an integer number (1503894600).
Almost surely, 253490291195 is an apocalyptic number.
53490291195 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
53490291195 is a deficient number, since it is larger than the sum of its proper divisors (42758963205).
53490291195 is a wasteful number, since it uses less digits than its factorization.
53490291195 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 75420.
The product of its (nonzero) digits is 437400, while the sum is 48.
The spelling of 53490291195 in words is "fifty-three billion, four hundred ninety million, two hundred ninety-one thousand, one hundred ninety-five".
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