5349703 has 4 divisors (see below), whose sum is σ = 5354640. Its totient is φ = 5344768.

The previous prime is 5349691. The next prime is 5349727. The reversal of 5349703 is 3079435.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 3079435 = 5 ⋅615887.

It is a cyclic number.

It is not a de Polignac number, because 5349703 - 2⁵ = 5349671 is a prime.

It is a Smith number, since the sum of its digits (31) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5349733) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 58 + ... + 3271.

It is an arithmetic number, because the mean of its divisors is an integer number (1338660).

Almost surely, 2^5349703 is an apocalyptic number.

5349703 is a deficient number, since it is larger than the sum of its proper divisors (4937).

5349703 is a wasteful number, since it uses less digits than its factorization.

5349703 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4936.

The product of its (nonzero) digits is 11340, while the sum is 31.

The square root of 5349703 is about 2312.9424982044. The cubic root of 5349703 is about 174.8946631385.

The spelling of 5349703 in words is "five million, three hundred forty-nine thousand, seven hundred three".