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5349757200205 = 51197268312731
BaseRepresentation
bin100110111011001011001…
…1000001010011101001101
3200221102122202222211002011
41031312112120022131031
51200122300320401310
615213351115101221
71061335653624235
oct115662630123515
920842582884064
105349757200205
111782901520820
1272499aa41811
132ca631571572
14146d02c94cc5
159425d2b478a
hex4dd9660a74d

5349757200205 has 8 divisors (see below), whose sum is σ = 7003318516704. Its totient is φ = 3890732509200.

The previous prime is 5349757200199. The next prime is 5349757200217. The reversal of 5349757200205 is 5020027579435.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 5349757200205 - 27 = 5349757200077 is a prime.

It is a super-3 number, since 3×53497572002053 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 48634156311 + ... + 48634156420.

It is an arithmetic number, because the mean of its divisors is an integer number (875414814588).

Almost surely, 25349757200205 is an apocalyptic number.

5349757200205 is a gapful number since it is divisible by the number (55) formed by its first and last digit.

It is an amenable number.

5349757200205 is a deficient number, since it is larger than the sum of its proper divisors (1653561316499).

5349757200205 is a wasteful number, since it uses less digits than its factorization.

5349757200205 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 97268312747.

The product of its (nonzero) digits is 2646000, while the sum is 49.

The spelling of 5349757200205 in words is "five trillion, three hundred forty-nine billion, seven hundred fifty-seven million, two hundred thousand, two hundred five".

Divisors: 1 5 11 55 97268312731 486341563655 1069951440041 5349757200205