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53513220402445 = 510702644080489
BaseRepresentation
bin11000010101011100001000…
…11111100010110100001101
321000110210222100011021121111
430022232010133202310031
524003230033410334240
6305451344543132021
714162126326213126
oct1412560437426415
9230423870137544
1053513220402445
11160619139152a1
1260032792a4011
1323b237632128b
14d300a746304d
1562c0059731ea
hex30ab847e2d0d

53513220402445 has 4 divisors (see below), whose sum is σ = 64215864482940. Its totient is φ = 42810576321952.

The previous prime is 53513220402427. The next prime is 53513220402469. The reversal of 53513220402445 is 54420402231535.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 41233003791849 + 12280216610596 = 6421293^2 + 3504314^2 .

It is a cyclic number.

It is not a de Polignac number, because 53513220402445 - 215 = 53513220369677 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 53513220402398 and 53513220402407.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5351322040240 + ... + 5351322040249.

It is an arithmetic number, because the mean of its divisors is an integer number (16053966120735).

Almost surely, 253513220402445 is an apocalyptic number.

It is an amenable number.

53513220402445 is a deficient number, since it is larger than the sum of its proper divisors (10702644080495).

53513220402445 is a wasteful number, since it uses less digits than its factorization.

53513220402445 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10702644080494.

The product of its (nonzero) digits is 576000, while the sum is 40.

The spelling of 53513220402445 in words is "fifty-three trillion, five hundred thirteen billion, two hundred twenty million, four hundred two thousand, four hundred forty-five".

Divisors: 1 5 10702644080489 53513220402445