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53520013 = 71753803
BaseRepresentation
bin1100110000101…
…0011010001101
310201201002122201
43030022122031
5102200120023
65151041501
71216625011
oct314123215
9121632581
1053520013
1128235418
1215b10291
13b11b661
147172541
154a72bad
hex330a68d

53520013 has 4 divisors (see below), whose sum is σ = 54273888. Its totient is φ = 52766140.

The previous prime is 53520007. The next prime is 53520031. The reversal of 53520013 is 31002535.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31002535 = 56200507.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-53520013 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53520083) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 376831 + ... + 376972.

It is an arithmetic number, because the mean of its divisors is an integer number (13568472).

Almost surely, 253520013 is an apocalyptic number.

It is an amenable number.

53520013 is a deficient number, since it is larger than the sum of its proper divisors (753875).

53520013 is an equidigital number, since it uses as much as digits as its factorization.

53520013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 753874.

The product of its (nonzero) digits is 450, while the sum is 19.

The square root of 53520013 is about 7315.7373517643. The cubic root of 53520013 is about 376.8530808638.

Adding to 53520013 its reverse (31002535), we get a palindrome (84522548).

The spelling of 53520013 in words is "fifty-three million, five hundred twenty thousand, thirteen".

Divisors: 1 71 753803 53520013