Base | Representation |
---|---|
bin | 11000010101101011100111… |
… | …11111100100110100010101 |
3 | 21000111121102200202110122201 |
4 | 30022311303333210310111 |
5 | 24003344100040134143 |
6 | 305455241510124501 |
7 | 14162542331441644 |
oct | 1412656377446425 |
9 | 230447380673581 |
10 | 53521533521173 |
11 | 1606539a407453 |
12 | 60049b9350731 |
13 | 23b309c6a6443 |
14 | d3065555735b |
15 | 62c3406be64d |
hex | 30ad73fe4d15 |
53521533521173 has 4 divisors (see below), whose sum is σ = 53522877006720. Its totient is φ = 53520190035628.
The previous prime is 53521533521149. The next prime is 53521533521221. The reversal of 53521533521173 is 37112533512535.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 53521533521173 - 29 = 53521533520661 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53521533521123) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 671683015 + ... + 671762692.
It is an arithmetic number, because the mean of its divisors is an integer number (13380719251680).
Almost surely, 253521533521173 is an apocalyptic number.
It is an amenable number.
53521533521173 is a deficient number, since it is larger than the sum of its proper divisors (1343485547).
53521533521173 is a wasteful number, since it uses less digits than its factorization.
53521533521173 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1343485546.
The product of its digits is 1417500, while the sum is 46.
The spelling of 53521533521173 in words is "fifty-three trillion, five hundred twenty-one billion, five hundred thirty-three million, five hundred twenty-one thousand, one hundred seventy-three".
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