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535313220034 = 2267656610017
BaseRepresentation
bin1111100101000110010…
…01111000000111000010
31220011201220021011021211
413302203021320013002
532232310141020114
61045530340040334
753450363202535
oct7624311700702
91804656234254
10535313220034
111970303a236a
12878b73930aa
133b63121a948
141bca3184a1c
15ddd0e346c4
hex7ca32781c2

535313220034 has 4 divisors (see below), whose sum is σ = 802969830054. Its totient is φ = 267656610016.

The previous prime is 535313219953. The next prime is 535313220049. The reversal of 535313220034 is 430022313535.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 430022313535 = 586004462707.

It can be written as a sum of positive squares in only one way, i.e., 470973375625 + 64339844409 = 686275^2 + 253653^2 .

It is a super-2 number, since 2×5353132200342 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 535313219978 and 535313220005.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 133828305007 + ... + 133828305010.

Almost surely, 2535313220034 is an apocalyptic number.

535313220034 is a deficient number, since it is larger than the sum of its proper divisors (267656610020).

535313220034 is a wasteful number, since it uses less digits than its factorization.

535313220034 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 267656610019.

The product of its (nonzero) digits is 32400, while the sum is 31.

Adding to 535313220034 its reverse (430022313535), we get a palindrome (965335533569).

The spelling of 535313220034 in words is "five hundred thirty-five billion, three hundred thirteen million, two hundred twenty thousand, thirty-four".

Divisors: 1 2 267656610017 535313220034