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5354145301 = 43124515007
BaseRepresentation
bin1001111110010000…
…11100011000010101
3111211010202202120211
410333020130120111
541431130122201
62243141525421
7246452325031
oct47710343025
914733682524
105354145301
1122a830367a
121055113871
1367433681b
1438b12b1c1
152150ad651
hex13f21c615

5354145301 has 4 divisors (see below), whose sum is σ = 5478660352. Its totient is φ = 5229630252.

The previous prime is 5354145281. The next prime is 5354145311. The reversal of 5354145301 is 1035414535.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5354145301 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5354145311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 62257461 + ... + 62257546.

It is an arithmetic number, because the mean of its divisors is an integer number (1369665088).

Almost surely, 25354145301 is an apocalyptic number.

It is an amenable number.

5354145301 is a deficient number, since it is larger than the sum of its proper divisors (124515051).

5354145301 is a wasteful number, since it uses less digits than its factorization.

5354145301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 124515050.

The product of its (nonzero) digits is 18000, while the sum is 31.

The square root of 5354145301 is about 73172.0253990553. The cubic root of 5354145301 is about 1749.4305958121.

Adding to 5354145301 its reverse (1035414535), we get a palindrome (6389559836).

The spelling of 5354145301 in words is "five billion, three hundred fifty-four million, one hundred forty-five thousand, three hundred one".

Divisors: 1 43 124515007 5354145301