Base | Representation |
---|---|
bin | 110001110111011000… |
… | …011011011100100101 |
3 | 12010012110122211020111 |
4 | 301313120123130211 |
5 | 1334123340001013 |
6 | 40332545333021 |
7 | 3603555512323 |
oct | 616730333445 |
9 | 163173584214 |
10 | 53542500133 |
11 | 20786388911 |
12 | a463337171 |
13 | 5083969b55 |
14 | 283cdd2d13 |
15 | 15d589973d |
hex | c7761b725 |
53542500133 has 4 divisors (see below), whose sum is σ = 53545662828. Its totient is φ = 53539337440.
The previous prime is 53542500119. The next prime is 53542500149. The reversal of 53542500133 is 33100524535.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 42535762564 + 11006737569 = 206242^2 + 104913^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53542500133 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 53542500095 and 53542500104.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53540500133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1555816 + ... + 1589857.
It is an arithmetic number, because the mean of its divisors is an integer number (13386415707).
Almost surely, 253542500133 is an apocalyptic number.
It is an amenable number.
53542500133 is a deficient number, since it is larger than the sum of its proper divisors (3162695).
53542500133 is a wasteful number, since it uses less digits than its factorization.
53542500133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3162694.
The product of its (nonzero) digits is 27000, while the sum is 31.
The spelling of 53542500133 in words is "fifty-three billion, five hundred forty-two million, five hundred thousand, one hundred thirty-three".
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