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53555334000034 = 226777667000017
BaseRepresentation
bin11000010110101010100101…
…01010001010110110100010
321000121211200022022200221011
430023111102222022312202
524004422311001000114
6305522551503451134
714165150046663046
oct1413252252126642
9230554608280834
1053555334000034
11160787649494a9
12600b470bb6aaa
1323b63282428a9
14d3214061a026
1562d16ccab1c4
hex30b552a8ada2

53555334000034 has 4 divisors (see below), whose sum is σ = 80333001000054. Its totient is φ = 26777667000016.

The previous prime is 53555334000023. The next prime is 53555334000059. The reversal of 53555334000034 is 43000043355535.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 50597116317225 + 2958217682809 = 7113165^2 + 1719947^2 .

It is a super-3 number, since 3×535553340000343 (a number of 42 digits) contains 333 as substring.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13388833500007 + ... + 13388833500010.

Almost surely, 253555334000034 is an apocalyptic number.

53555334000034 is a deficient number, since it is larger than the sum of its proper divisors (26777667000020).

53555334000034 is a wasteful number, since it uses less digits than its factorization.

53555334000034 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26777667000019.

The product of its (nonzero) digits is 810000, while the sum is 40.

Adding to 53555334000034 its reverse (43000043355535), we get a palindrome (96555377355569).

The spelling of 53555334000034 in words is "fifty-three trillion, five hundred fifty-five billion, three hundred thirty-four million, thirty-four", and thus it is an aban number.

Divisors: 1 2 26777667000017 53555334000034