Base | Representation |
---|---|
bin | 100111000000001001010… |
… | …0010001010100000110011 |
3 | 200222110012120222220001121 |
4 | 1032000102202022200303 |
5 | 1200311130103200001 |
6 | 15222314141043111 |
7 | 1062164312220256 |
oct | 116002242124063 |
9 | 20873176886047 |
10 | 5360430131251 |
11 | 1787389076898 |
12 | 726a79256497 |
13 | 2cb6427b1290 |
14 | 14763654709d |
15 | 946852996a1 |
hex | 4e01288a833 |
5360430131251 has 16 divisors (see below), whose sum is σ = 6069730887360. Its totient is φ = 4699146453120.
The previous prime is 5360430131207. The next prime is 5360430131261. The reversal of 5360430131251 is 1521310340635.
It is a cyclic number.
It is not a de Polignac number, because 5360430131251 - 217 = 5360430000179 is a prime.
It is a super-2 number, since 2×53604301312512 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5360430131261) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 116523295 + ... + 116569288.
It is an arithmetic number, because the mean of its divisors is an integer number (379358180460).
Almost surely, 25360430131251 is an apocalyptic number.
5360430131251 is a deficient number, since it is larger than the sum of its proper divisors (709300756109).
5360430131251 is a wasteful number, since it uses less digits than its factorization.
5360430131251 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 233092686.
The product of its (nonzero) digits is 32400, while the sum is 34.
Adding to 5360430131251 its reverse (1521310340635), we get a palindrome (6881740471886).
The spelling of 5360430131251 in words is "five trillion, three hundred sixty billion, four hundred thirty million, one hundred thirty-one thousand, two hundred fifty-one".
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