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53612140031 = 70437612117
BaseRepresentation
bin110001111011100010…
…000101010111111111
312010101022200220012222
4301323202011113333
51334244201440111
640343514115555
73605362446152
oct617342052777
9163338626188
1053612140031
112081172334a
12a48271bbbb
1350952107a8
14284835dc99
1515dba537db
hexc7b8855ff

53612140031 has 4 divisors (see below), whose sum is σ = 53619759192. Its totient is φ = 53604520872.

The previous prime is 53612140013. The next prime is 53612140033. The reversal of 53612140031 is 13004121635.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 53612140031 - 218 = 53611877887 is a prime.

It is a super-2 number, since 2×536121400312 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53612140033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3799016 + ... + 3813101.

It is an arithmetic number, because the mean of its divisors is an integer number (13404939798).

Almost surely, 253612140031 is an apocalyptic number.

53612140031 is a deficient number, since it is larger than the sum of its proper divisors (7619161).

53612140031 is an equidigital number, since it uses as much as digits as its factorization.

53612140031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7619160.

The product of its (nonzero) digits is 2160, while the sum is 26.

Adding to 53612140031 its reverse (13004121635), we get a palindrome (66616261666).

The spelling of 53612140031 in words is "fifty-three billion, six hundred twelve million, one hundred forty thousand, thirty-one".

Divisors: 1 7043 7612117 53612140031