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5361214153 = 9771976871
BaseRepresentation
bin1001111111000110…
…11010001011001001
3111211122001220020011
410333203122023021
541434432323103
62243553231521
7246566365651
oct47743321311
914748056204
105361214153
1123012a15a9
1210575625a1
13675940189
1438c04b361
15215a07d6d
hex13f8da2c9

5361214153 has 8 divisors (see below), whose sum is σ = 5424088320. Its totient is φ = 5298495360.

The previous prime is 5361214151. The next prime is 5361214207. The reversal of 5361214153 is 3514121635.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 5361214153 - 21 = 5361214151 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5361214151) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 31308 + ... + 108178.

It is an arithmetic number, because the mean of its divisors is an integer number (678011040).

Almost surely, 25361214153 is an apocalyptic number.

It is an amenable number.

5361214153 is a deficient number, since it is larger than the sum of its proper divisors (62874167).

5361214153 is an equidigital number, since it uses as much as digits as its factorization.

5361214153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 77687.

The product of its digits is 10800, while the sum is 31.

The square root of 5361214153 is about 73220.3124344604. The cubic root of 5361214153 is about 1750.2001570244.

Adding to 5361214153 its reverse (3514121635), we get a palindrome (8875335788).

The spelling of 5361214153 in words is "five billion, three hundred sixty-one million, two hundred fourteen thousand, one hundred fifty-three".

Divisors: 1 97 719 69743 76871 7456487 55270249 5361214153