Base | Representation |
---|---|
bin | 11000011000010100111010… |
… | …00111111000010011101111 |
3 | 21000211022000120201010020010 |
4 | 30030022131013320103233 |
5 | 24011341212434032411 |
6 | 310005112121224303 |
7 | 14202240456640023 |
oct | 1414123507702357 |
9 | 230738016633203 |
10 | 53612417877231 |
11 | 1609a998245314 |
12 | 601a542332093 |
13 | 23bb8247a5615 |
14 | d34bd7a9c383 |
15 | 62e8ae4d77a6 |
hex | 30c29d1f84ef |
53612417877231 has 8 divisors (see below), whose sum is σ = 71531425611520. Its totient is φ = 35717511030552.
The previous prime is 53612417877223. The next prime is 53612417877233. The reversal of 53612417877231 is 13277871421635.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 53612417877231 - 23 = 53612417877223 is a prime.
It is a super-2 number, since 2×536124178772312 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53612417877233) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6025216711 + ... + 6025225608.
It is an arithmetic number, because the mean of its divisors is an integer number (8941428201440).
Almost surely, 253612417877231 is an apocalyptic number.
53612417877231 is a deficient number, since it is larger than the sum of its proper divisors (17919007734289).
53612417877231 is a wasteful number, since it uses less digits than its factorization.
53612417877231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12050443805.
The product of its digits is 11854080, while the sum is 57.
The spelling of 53612417877231 in words is "fifty-three trillion, six hundred twelve billion, four hundred seventeen million, eight hundred seventy-seven thousand, two hundred thirty-one".
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