Base | Representation |
---|---|
bin | 110001111100001100… |
… | …010000001001011011 |
3 | 12010102002111111200202 |
4 | 301330030100021123 |
5 | 1334310014203303 |
6 | 40344551052415 |
7 | 3605555426105 |
oct | 617414201133 |
9 | 163362444622 |
10 | 53623194203 |
11 | 20817993527 |
12 | a48637110b |
13 | 50975b1117 |
14 | 28499da575 |
15 | 15dc9d8c88 |
hex | c7c31025b |
53623194203 has 4 divisors (see below), whose sum is σ = 55072469760. Its totient is φ = 52173918648.
The previous prime is 53623194199. The next prime is 53623194271. The reversal of 53623194203 is 30249132635.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30249132635 = 5 ⋅6049826527.
It is a cyclic number.
It is not a de Polignac number, because 53623194203 - 22 = 53623194199 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (53623694203) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 724637723 + ... + 724637796.
It is an arithmetic number, because the mean of its divisors is an integer number (13768117440).
Almost surely, 253623194203 is an apocalyptic number.
53623194203 is a deficient number, since it is larger than the sum of its proper divisors (1449275557).
53623194203 is a wasteful number, since it uses less digits than its factorization.
53623194203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1449275556.
The product of its (nonzero) digits is 116640, while the sum is 38.
The spelling of 53623194203 in words is "fifty-three billion, six hundred twenty-three million, one hundred ninety-four thousand, two hundred three".
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