53625305145233 has 4 divisors (see below), whose sum is σ = 53625319801200. Its totient is φ = 53625290489268.

The previous prime is 53625305145227. The next prime is 53625305145271. The reversal of 53625305145233 is 33254150352635.

53625305145233 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 53625305145233 - 2⁶ = 53625305145169 is a prime.

It is a super-3 number, since 3×53625305145233³ (a number of 42 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (53625305145283) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3255866 + ... + 10855932.

It is an arithmetic number, because the mean of its divisors is an integer number (13406329950300).

Almost surely, 2^{53625305145233} is an apocalyptic number.

It is an amenable number.

53625305145233 is a deficient number, since it is larger than the sum of its proper divisors (14655967).

53625305145233 is an equidigital number, since it uses as much as digits as its factorization.

53625305145233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14655966.

The product of its (nonzero) digits is 4860000, while the sum is 47.

Adding to 53625305145233 its reverse (33254150352635), we get a palindrome (86879455497868).

The spelling of 53625305145233 in words is "fifty-three trillion, six hundred twenty-five billion, three hundred five million, one hundred forty-five thousand, two hundred thirty-three".