Base | Representation |
---|---|
bin | 1001111111011101… |
… | …00100101111001001 |
3 | 111211211120121002221 |
4 | 10333232210233021 |
5 | 41441210003001 |
6 | 2244140054041 |
7 | 246633306022 |
oct | 47756445711 |
9 | 14754517087 |
10 | 5364141001 |
11 | 2302a1058a |
12 | 1058534321 |
13 | 67642643b |
14 | 38c5adc49 |
15 | 215dd51a1 |
hex | 13fba4bc9 |
5364141001 has 4 divisors (see below), whose sum is σ = 5432041600. Its totient is φ = 5296240404.
The previous prime is 5364140989. The next prime is 5364141059. The reversal of 5364141001 is 1001414635.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5364141001 - 29 = 5364140489 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5364141071) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33950181 + ... + 33950338.
It is an arithmetic number, because the mean of its divisors is an integer number (1358010400).
Almost surely, 25364141001 is an apocalyptic number.
It is an amenable number.
5364141001 is a deficient number, since it is larger than the sum of its proper divisors (67900599).
5364141001 is an equidigital number, since it uses as much as digits as its factorization.
5364141001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 67900598.
The product of its (nonzero) digits is 1440, while the sum is 25.
The square root of 5364141001 is about 73240.2962924100. The cubic root of 5364141001 is about 1750.5185947127.
Adding to 5364141001 its reverse (1001414635), we get a palindrome (6365555636).
The spelling of 5364141001 in words is "five billion, three hundred sixty-four million, one hundred forty-one thousand, one".
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