Base | Representation |
---|---|
bin | 11000011001001111111111… |
… | …00100000101111101111111 |
3 | 21000221022212221120211112110 |
4 | 30030213333210011331333 |
5 | 24012401141324231310 |
6 | 310031435224305103 |
7 | 14204442440221524 |
oct | 1414477744057577 |
9 | 230838787524473 |
10 | 53644134211455 |
11 | 16102393298687 |
12 | 6024714012193 |
13 | 23c180a6159a8 |
14 | d3656604114b |
15 | 630618b3ed20 |
hex | 30c9ff905f7f |
53644134211455 has 16 divisors (see below), whose sum is σ = 88599344246784. Its totient is φ = 27687295076640.
The previous prime is 53644134211453. The next prime is 53644134211463. The reversal of 53644134211455 is 55411243144635.
It is not a de Polignac number, because 53644134211455 - 21 = 53644134211453 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53644134211453) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 57681864279 + ... + 57681865208.
It is an arithmetic number, because the mean of its divisors is an integer number (5537459015424).
Almost surely, 253644134211455 is an apocalyptic number.
53644134211455 is a deficient number, since it is larger than the sum of its proper divisors (34955210035329).
53644134211455 is a wasteful number, since it uses less digits than its factorization.
53644134211455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 115363729526.
The product of its digits is 3456000, while the sum is 48.
The spelling of 53644134211455 in words is "fifty-three trillion, six hundred forty-four billion, one hundred thirty-four million, two hundred eleven thousand, four hundred fifty-five".
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