Base | Representation |
---|---|
bin | 100111000010001110100… |
… | …1011111010010011111011 |
3 | 200222212202101000112121220 |
4 | 1032010131023322103323 |
5 | 1200344310334030040 |
6 | 15224334111403123 |
7 | 1062413214002256 |
oct | 116043513722373 |
9 | 20885671015556 |
10 | 5364903814395 |
11 | 1789274382194 |
12 | 7279075234a3 |
13 | 2cbba65a2378 |
14 | 14793c76209d |
15 | 94847dda2d0 |
hex | 4e11d2fa4fb |
5364903814395 has 32 divisors (see below), whose sum is σ = 8962830040320. Its totient is φ = 2736798261120.
The previous prime is 5364903814381. The next prime is 5364903814471. The reversal of 5364903814395 is 5934183094635.
It is not a de Polignac number, because 5364903814395 - 27 = 5364903814267 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 57584821 + ... + 57677910.
It is an arithmetic number, because the mean of its divisors is an integer number (280088438760).
Almost surely, 25364903814395 is an apocalyptic number.
5364903814395 is a deficient number, since it is larger than the sum of its proper divisors (3597926225925).
5364903814395 is a wasteful number, since it uses less digits than its factorization.
5364903814395 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 115262875.
The product of its (nonzero) digits is 41990400, while the sum is 60.
The spelling of 5364903814395 in words is "five trillion, three hundred sixty-four billion, nine hundred three million, eight hundred fourteen thousand, three hundred ninety-five".
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