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53654112113 = 72929113999
BaseRepresentation
bin110001111110000010…
…001100011101110001
312010111020200022002112
4301332002030131301
51334340423041423
640352013455105
73606412266560
oct617602143561
9163436608075
1053654112113
1120833390618
12a4947a1495
1350a0b17b44
14284db67bd7
1515e0594a78
hexc7e08c771

53654112113 has 12 divisors (see below), whose sum is σ = 63506352000. Its totient is φ = 44403398256.

The previous prime is 53654112089. The next prime is 53654112119. The reversal of 53654112113 is 31121145635.

53654112113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 53654112113 - 216 = 53654046577 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 53654112113.

It is not an unprimeable number, because it can be changed into a prime (53654112119) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 4551113 + ... + 4562886.

It is an arithmetic number, because the mean of its divisors is an integer number (5292196000).

Almost surely, 253654112113 is an apocalyptic number.

It is an amenable number.

53654112113 is a deficient number, since it is larger than the sum of its proper divisors (9852239887).

53654112113 is an equidigital number, since it uses as much as digits as its factorization.

53654112113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9114064 (or 9114035 counting only the distinct ones).

The product of its digits is 10800, while the sum is 32.

Adding to 53654112113 its reverse (31121145635), we get a palindrome (84775257748).

The spelling of 53654112113 in words is "fifty-three billion, six hundred fifty-four million, one hundred twelve thousand, one hundred thirteen".

Divisors: 1 7 29 203 841 5887 9113999 63797993 264305971 1850141797 7664873159 53654112113