Base | Representation |
---|---|
bin | 11000011010001101101011… |
… | …00110101101100001011111 |
3 | 21001001111101001122211001020 |
4 | 30031012311212231201133 |
5 | 24013422003244402033 |
6 | 310054553433415223 |
7 | 14210024241266460 |
oct | 1415066546554137 |
9 | 231044331584036 |
10 | 53677253122143 |
11 | 1611543902a452 |
12 | 602b01756a513 |
13 | 23c4987bc7471 |
14 | d37dc87a6d67 |
15 | 63140649a6b3 |
hex | 30d1b59ad85f |
53677253122143 has 16 divisors (see below), whose sum is σ = 81794221426176. Its totient is φ = 30672599104800.
The previous prime is 53677253122109. The next prime is 53677253122247. The reversal of 53677253122143 is 34122135277635.
It is not a de Polignac number, because 53677253122143 - 216 = 53677253056607 is a prime.
It is a super-2 number, since 2×536772531221432 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53677253122043) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 925030 + ... + 10402412.
It is an arithmetic number, because the mean of its divisors is an integer number (5112138839136).
Almost surely, 253677253122143 is an apocalyptic number.
53677253122143 is a deficient number, since it is larger than the sum of its proper divisors (28116968304033).
53677253122143 is a wasteful number, since it uses less digits than its factorization.
53677253122143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9747094.
The product of its digits is 6350400, while the sum is 51.
Adding to 53677253122143 its reverse (34122135277635), we get a palindrome (87799388399778).
The spelling of 53677253122143 in words is "fifty-three trillion, six hundred seventy-seven billion, two hundred fifty-three million, one hundred twenty-two thousand, one hundred forty-three".
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