Base | Representation |
---|---|
bin | 110010000000100101… |
… | …100110101010100111 |
3 | 12010121020021122010022 |
4 | 302000211212222213 |
5 | 1334432404331103 |
6 | 40400143545355 |
7 | 3610442351303 |
oct | 620045465247 |
9 | 163536248108 |
10 | 53696948903 |
11 | 20855589524 |
12 | a4a6bbb25b |
13 | 50a9965960 |
14 | 2855718d03 |
15 | 15e4207138 |
hex | c80966aa7 |
53696948903 has 16 divisors (see below), whose sum is σ = 58417719360. Its totient is φ = 49060975104.
The previous prime is 53696948807. The next prime is 53696948917. The reversal of 53696948903 is 30984969635.
It is a cyclic number.
It is not a de Polignac number, because 53696948903 - 214 = 53696932519 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53696948983) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3061583 + ... + 3079071.
It is an arithmetic number, because the mean of its divisors is an integer number (3651107460).
Almost surely, 253696948903 is an apocalyptic number.
53696948903 is a deficient number, since it is larger than the sum of its proper divisors (4720770457).
53696948903 is a wasteful number, since it uses less digits than its factorization.
53696948903 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19898.
The product of its (nonzero) digits is 37791360, while the sum is 62.
The spelling of 53696948903 in words is "fifty-three billion, six hundred ninety-six million, nine hundred forty-eight thousand, nine hundred three".
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