Base | Representation |
---|---|
bin | 11000011010110011010101… |
… | …01110011001110101100101 |
3 | 21001010102120010110011201101 |
4 | 30031121222232121311211 |
5 | 24014234410222341231 |
6 | 310112140011400101 |
7 | 14211341256240001 |
oct | 1415315256316545 |
9 | 231112503404641 |
10 | 53697471683941 |
11 | 16122a7396a158 |
12 | 6032b1a753031 |
13 | 23c685a957cb7 |
14 | d38d85b03701 |
15 | 631bdb4da661 |
hex | 30d66ab99d65 |
53697471683941 has 4 divisors (see below), whose sum is σ = 53697497124384. Its totient is φ = 53697446243500.
The previous prime is 53697471683771. The next prime is 53697471683959. The reversal of 53697471683941 is 14938617479635.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 53697471683941 - 241 = 51498448428389 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53697471683441) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9236035 + ... + 13881616.
It is an arithmetic number, because the mean of its divisors is an integer number (13424374281096).
Almost surely, 253697471683941 is an apocalyptic number.
It is an amenable number.
53697471683941 is a deficient number, since it is larger than the sum of its proper divisors (25440443).
53697471683941 is a wasteful number, since it uses less digits than its factorization.
53697471683941 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 25440442.
The product of its digits is 823011840, while the sum is 73.
The spelling of 53697471683941 in words is "fifty-three trillion, six hundred ninety-seven billion, four hundred seventy-one million, six hundred eighty-three thousand, nine hundred forty-one".
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