Base | Representation |
---|---|
bin | 1010000000010011… |
… | …10000110011100001 |
3 | 111212022222200221202 |
4 | 11000021300303201 |
5 | 42000021041241 |
6 | 2244552530545 |
7 | 250051012256 |
oct | 50011606341 |
9 | 14768880852 |
10 | 5371268321 |
11 | 2306a39431 |
12 | 105a9b0a55 |
13 | 677a505a3 |
14 | 38d50742d |
15 | 216841d9b |
hex | 140270ce1 |
5371268321 has 4 divisors (see below), whose sum is σ = 5556484500. Its totient is φ = 5186052144.
The previous prime is 5371268317. The next prime is 5371268333. The reversal of 5371268321 is 1238621735.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 4027679296 + 1343589025 = 63464^2 + 36655^2 .
It is a cyclic number.
It is not a de Polignac number, because 5371268321 - 22 = 5371268317 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5371268521) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 92608046 + ... + 92608103.
It is an arithmetic number, because the mean of its divisors is an integer number (1389121125).
Almost surely, 25371268321 is an apocalyptic number.
It is an amenable number.
5371268321 is a deficient number, since it is larger than the sum of its proper divisors (185216179).
5371268321 is a wasteful number, since it uses less digits than its factorization.
5371268321 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 185216178.
The product of its digits is 60480, while the sum is 38.
The square root of 5371268321 is about 73288.9372347560. The cubic root of 5371268321 is about 1751.2935547315.
The spelling of 5371268321 in words is "five billion, three hundred seventy-one million, two hundred sixty-eight thousand, three hundred twenty-one".
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