5372029333 has 4 divisors (see below), whose sum is σ = 5860395648. Its totient is φ = 4883663020.

The previous prime is 5372029319. The next prime is 5372029337. The reversal of 5372029333 is 3339202735.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5372029333 - 2⁵ = 5372029301 is a prime.

It is a super-2 number, since 2×5372029333² = 57717398309224849778, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5372029292 and 5372029301.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5372029337) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 244183141 + ... + 244183162.

It is an arithmetic number, because the mean of its divisors is an integer number (1465098912).

Almost surely, 2^5372029333 is an apocalyptic number.

It is an amenable number.

5372029333 is a deficient number, since it is larger than the sum of its proper divisors (488366315).

5372029333 is a wasteful number, since it uses less digits than its factorization.

5372029333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 488366314.

The product of its (nonzero) digits is 102060, while the sum is 37.

The square root of 5372029333 is about 73294.1289122123. The cubic root of 5372029333 is about 1751.3762597460.

It can be divided in two parts, 537202 and 9333, that added together give a triangular number (546535 = T₁₀₄₅).

The spelling of 5372029333 in words is "five billion, three hundred seventy-two million, twenty-nine thousand, three hundred thirty-three".