Base | Representation |
---|---|
bin | 11000011101000011000001… |
… | …11000101010110100101001 |
3 | 21001101210200110010012011110 |
4 | 30032201200320222310221 |
5 | 24022020403144422441 |
6 | 310211414554220533 |
7 | 14220042054232422 |
oct | 1416414070526451 |
9 | 231353613105143 |
10 | 53774616014121 |
11 | 16152760925232 |
12 | 6045a6a124749 |
13 | 2400c03270852 |
14 | d3c9c34c6649 |
15 | 633c03e24b16 |
hex | 30e860e2ad29 |
53774616014121 has 24 divisors (see below), whose sum is σ = 76170262339584. Its totient is φ = 33738692972800.
The previous prime is 53774616014101. The next prime is 53774616014153. The reversal of 53774616014121 is 12141061647735.
It is not a de Polignac number, because 53774616014121 - 25 = 53774616014089 is a prime.
It is not an unprimeable number, because it can be changed into a prime (53774616014101) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 11038936 + ... + 15146198.
It is an arithmetic number, because the mean of its divisors is an integer number (3173760930816).
Almost surely, 253774616014121 is an apocalyptic number.
53774616014121 is a gapful number since it is divisible by the number (51) formed by its first and last digit.
It is an amenable number.
53774616014121 is a deficient number, since it is larger than the sum of its proper divisors (22395646325463).
53774616014121 is a wasteful number, since it uses less digits than its factorization.
53774616014121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4122401 (or 4122384 counting only the distinct ones).
The product of its (nonzero) digits is 846720, while the sum is 48.
The spelling of 53774616014121 in words is "fifty-three trillion, seven hundred seventy-four billion, six hundred sixteen million, fourteen thousand, one hundred twenty-one".
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